16x^2+60x-54=0

Solution for 16x^2+60x-54=0 equation:

16x^2+60x-54=0

a = 16; b = 60; c = -54;
Δ = b2-4ac
Δ = 602-4·16·(-54)
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7056}=84$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-84}{2*16}=\frac{-144}{32}
=-4+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+84}{2*16}=\frac{24}{32}
=3/4
$